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04-08-2011, 11:35 AM   #27
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Re: 48÷2(9+3) = ??

Quote:
 Originally Posted by Numinous But it means it CAN be set up as a fraction, it just doesn't mean that's always the case.
it doesnt mean you can set it up as a fraction, if you arent dividing by the rest of the equation you cant take the whole thing and treat it as you are by setting it up as a fraction.

Quote:
 Originally Posted by Numinous First, you didn't treat it as 48/2*(9+3), you treated it as (48/2)*(9+3). See how brackets make a difference? Second, you have no proof it isn't to be treated as a fraction, since THE ANNOTATION THAT WOULD CLARIFY IF IT'S A DIVISION OR A FRACTION IS ABSENT. Therefore it's faulty! .
what dont you understand about order of operations, 48/2*(9+3) is suppose to be treated as (48/2) x (9+3). that is the order of operations, you solve in the bracket, the you go from left to right.

Quote:
 Originally Posted by Numinous Edit: Oh, and you changed your mind about the result? Was it because you didn't think at first or the equation is ambiguous enough for you to change sides?
i did not change my mind once.